5+2sqrt{5}=p+xsqrt{5} eching

$$5+2 \sqrt{ 5 } = p+x \sqrt{ 5 }$$

x uchun yechish

$$x=-\frac{\sqrt{5}p}{5}+\sqrt{5}+2$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$p+x\sqrt{5}=5+2\sqrt{5}$$

Ikkala tarafdan p ni ayirish.

$$x\sqrt{5}=5+2\sqrt{5}-p$$

Tenglama standart shaklda.

$$\sqrt{5}x=-p+2\sqrt{5}+5$$

Ikki tarafini \sqrt{5} ga bo‘ling.

$$\frac{\sqrt{5}x}{\sqrt{5}}=\frac{-p+2\sqrt{5}+5}{\sqrt{5}}$$

\sqrt{5} ga bo'lish \sqrt{5} ga ko'paytirishni bekor qiladi.

$$x=\frac{-p+2\sqrt{5}+5}{\sqrt{5}}$$

5+2\sqrt{5}-p ni \sqrt{5} ga bo'lish.

$$x=\frac{\sqrt{5}\left(-p+2\sqrt{5}+5\right)}{5}$$

p uchun yechish

$$p=\sqrt{5}\left(-x+\sqrt{5}+2\right)$$