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factor(5x^{2}-6x-3)
-6x ni olish uchun -7x va x ni birlashtirish.
5x^{2}-6x-3=0
Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.
x=\frac{-\left(-6\right)±\sqrt{\left(-6\right)^{2}-4\times 5\left(-3\right)}}{2\times 5}
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-\left(-6\right)±\sqrt{36-4\times 5\left(-3\right)}}{2\times 5}
-6 kvadratini chiqarish.
x=\frac{-\left(-6\right)±\sqrt{36-20\left(-3\right)}}{2\times 5}
-4 ni 5 marotabaga ko'paytirish.
x=\frac{-\left(-6\right)±\sqrt{36+60}}{2\times 5}
-20 ni -3 marotabaga ko'paytirish.
x=\frac{-\left(-6\right)±\sqrt{96}}{2\times 5}
36 ni 60 ga qo'shish.
x=\frac{-\left(-6\right)±4\sqrt{6}}{2\times 5}
96 ning kvadrat ildizini chiqarish.
x=\frac{6±4\sqrt{6}}{2\times 5}
-6 ning teskarisi 6 ga teng.
x=\frac{6±4\sqrt{6}}{10}
2 ni 5 marotabaga ko'paytirish.
x=\frac{4\sqrt{6}+6}{10}
x=\frac{6±4\sqrt{6}}{10} tenglamasini yeching, bunda ± musbat. 6 ni 4\sqrt{6} ga qo'shish.
x=\frac{2\sqrt{6}+3}{5}
6+4\sqrt{6} ni 10 ga bo'lish.
x=\frac{6-4\sqrt{6}}{10}
x=\frac{6±4\sqrt{6}}{10} tenglamasini yeching, bunda ± manfiy. 6 dan 4\sqrt{6} ni ayirish.
x=\frac{3-2\sqrt{6}}{5}
6-4\sqrt{6} ni 10 ga bo'lish.
5x^{2}-6x-3=5\left(x-\frac{2\sqrt{6}+3}{5}\right)\left(x-\frac{3-2\sqrt{6}}{5}\right)
ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{3+2\sqrt{6}}{5} ga va x_{2} uchun \frac{3-2\sqrt{6}}{5} ga bo‘ling.
5x^{2}-6x-3
-6x ni olish uchun -7x va x ni birlashtirish.