5x^2-20x eching

$$5 x ^ { 2 } - 20 x$$

Omil

$$5x\left(x-4\right)$$

Yechim qadamlari

5 omili.

$$5\left(x^{2}-4x\right)$$

Hisoblang: x^{2}-4x. x omili.

$$x\left(x-4\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$5x\left(x-4\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$5x^{2}-20x=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-\left(-20\right)±\sqrt{\left(-20\right)^{2}}}{2\times 5}$$

\left(-20\right)^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-20\right)±20}{2\times 5}$$

-20 ning teskarisi 20 ga teng.

$$x=\frac{20±20}{2\times 5}$$

2 ni 5 marotabaga ko'paytirish.

$$x=\frac{20±20}{10}$$

x=\frac{20±20}{10} tenglamasini yeching, bunda ± musbat. 20 ni 20 ga qo'shish.

$$x=\frac{40}{10}$$

40 ni 10 ga bo'lish.

$$x=4$$

x=\frac{20±20}{10} tenglamasini yeching, bunda ± manfiy. 20 dan 20 ni ayirish.

$$x=\frac{0}{10}$$

0 ni 10 ga bo'lish.

$$x=0$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 4 ga va x_{2} uchun 0 ga bo‘ling.

$$5x^{2}-20x=5\left(x-4\right)x$$

Baholash

$$5x\left(x-4\right)$$