5x^2+27=6 eching

$$5 x ^ { 2 } + 27 = 6$$

x uchun yechish (complex solution)

$$x=-\frac{\sqrt{105}i}{5}\approx -0-2,049390153i$$

$$x=\frac{\sqrt{105}i}{5}\approx 2,049390153i$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 27 ni ayirish.

$$5x^{2}=6-27$$

-21 olish uchun 6 dan 27 ni ayirish.

$$5x^{2}=-21$$

Ikki tarafini 5 ga bo‘ling.

$$x^{2}=-\frac{21}{5}$$

Tenglama yechildi.

$$x=\frac{\sqrt{105}i}{5} x=-\frac{\sqrt{105}i}{5}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 6 ni ayirish.

$$5x^{2}+27-6=0$$

21 olish uchun 27 dan 6 ni ayirish.

$$5x^{2}+21=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 5 ni a, 0 ni b va 21 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 5\times 21}}{2\times 5}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 5\times 21}}{2\times 5}$$

-4 ni 5 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-20\times 21}}{2\times 5}$$

-20 ni 21 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-420}}{2\times 5}$$

-420 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{105}i}{2\times 5}$$

2 ni 5 marotabaga ko'paytirish.

$$x=\frac{0±2\sqrt{105}i}{10}$$

x=\frac{0±2\sqrt{105}i}{10} tenglamasini yeching, bunda ± musbat.

$$x=\frac{\sqrt{105}i}{5}$$

x=\frac{0±2\sqrt{105}i}{10} tenglamasini yeching, bunda ± manfiy.

$$x=-\frac{\sqrt{105}i}{5}$$

Tenglama yechildi.

$$x=\frac{\sqrt{105}i}{5} x=-\frac{\sqrt{105}i}{5}$$