5x^2+238-70x eching

$$5 x ^ { 2 } + 238 - 70 x$$

Omil

$$5\left(x-\left(-\frac{\sqrt{35}}{5}+7\right)\right)\left(x-\left(\frac{\sqrt{35}}{5}+7\right)\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$5x^{2}-70x+238=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-\left(-70\right)±\sqrt{\left(-70\right)^{2}-4\times 5\times 238}}{2\times 5}$$

-70 kvadratini chiqarish.

$$x=\frac{-\left(-70\right)±\sqrt{4900-4\times 5\times 238}}{2\times 5}$$

-4 ni 5 marotabaga ko'paytirish.

$$x=\frac{-\left(-70\right)±\sqrt{4900-20\times 238}}{2\times 5}$$

-20 ni 238 marotabaga ko'paytirish.

$$x=\frac{-\left(-70\right)±\sqrt{4900-4760}}{2\times 5}$$

4900 ni -4760 ga qo'shish.

$$x=\frac{-\left(-70\right)±\sqrt{140}}{2\times 5}$$

140 ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-70\right)±2\sqrt{35}}{2\times 5}$$

-70 ning teskarisi 70 ga teng.

$$x=\frac{70±2\sqrt{35}}{2\times 5}$$

2 ni 5 marotabaga ko'paytirish.

$$x=\frac{70±2\sqrt{35}}{10}$$

x=\frac{70±2\sqrt{35}}{10} tenglamasini yeching, bunda ± musbat. 70 ni 2\sqrt{35} ga qo'shish.

$$x=\frac{2\sqrt{35}+70}{10}$$

70+2\sqrt{35} ni 10 ga bo'lish.

$$x=\frac{\sqrt{35}}{5}+7$$

x=\frac{70±2\sqrt{35}}{10} tenglamasini yeching, bunda ± manfiy. 70 dan 2\sqrt{35} ni ayirish.

$$x=\frac{70-2\sqrt{35}}{10}$$

70-2\sqrt{35} ni 10 ga bo'lish.

$$x=-\frac{\sqrt{35}}{5}+7$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 7+\frac{\sqrt{35}}{5} ga va x_{2} uchun 7-\frac{\sqrt{35}}{5} ga bo‘ling.

$$5x^{2}-70x+238=5\left(x-\left(\frac{\sqrt{35}}{5}+7\right)\right)\left(x-\left(-\frac{\sqrt{35}}{5}+7\right)\right)$$

Baholash

$$5x^{2}-70x+238$$