m uchun yechish
m=-\frac{\sqrt{10}}{5}\approx -0,632455532
m=\frac{\sqrt{10}}{5}\approx 0,632455532
Baham ko'rish
Klipbordga nusxa olish
5t^{2}+13t-6=0
m^{2} uchun t ni almashtiring.
t=\frac{-13±\sqrt{13^{2}-4\times 5\left(-6\right)}}{2\times 5}
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni bu formula bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat tenglamada a uchun 5 ni, b uchun 13 ni va c uchun -6 ni ayiring.
t=\frac{-13±17}{10}
Hisoblarni amalga oshiring.
t=\frac{2}{5} t=-3
t=\frac{-13±17}{10} tenglamasini ± plus va ± minus boʻlgan holatida ishlang.
m=\frac{\sqrt{10}}{5} m=-\frac{\sqrt{10}}{5}
m=t^{2} boʻlganda, yechimlar musbat t uchun m=±\sqrt{t} hisoblanishi orqali olinadi.
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