5m^2+7=25 eching

$$5 m ^ { 2 } + 7 = 25$$

m uchun yechish

$$m = \frac{3 \sqrt{10}}{5} \approx 1,897366596$$

$$m = -\frac{3 \sqrt{10}}{5} \approx -1,897366596$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 7 ni ayirish.

$$5m^{2}=25-7$$

18 olish uchun 25 dan 7 ni ayirish.

$$5m^{2}=18$$

Ikki tarafini 5 ga bo‘ling.

$$m^{2}=\frac{18}{5}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$m=\frac{3\sqrt{10}}{5} m=-\frac{3\sqrt{10}}{5}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 25 ni ayirish.

$$5m^{2}+7-25=0$$

-18 olish uchun 7 dan 25 ni ayirish.

$$5m^{2}-18=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 5 ni a, 0 ni b va -18 ni c bilan almashtiring.

$$m=\frac{0±\sqrt{0^{2}-4\times 5\left(-18\right)}}{2\times 5}$$

0 kvadratini chiqarish.

$$m=\frac{0±\sqrt{-4\times 5\left(-18\right)}}{2\times 5}$$

-4 ni 5 marotabaga ko'paytirish.

$$m=\frac{0±\sqrt{-20\left(-18\right)}}{2\times 5}$$

-20 ni -18 marotabaga ko'paytirish.

$$m=\frac{0±\sqrt{360}}{2\times 5}$$

360 ning kvadrat ildizini chiqarish.

$$m=\frac{0±6\sqrt{10}}{2\times 5}$$

2 ni 5 marotabaga ko'paytirish.

$$m=\frac{0±6\sqrt{10}}{10}$$

m=\frac{0±6\sqrt{10}}{10} tenglamasini yeching, bunda ± musbat.

$$m=\frac{3\sqrt{10}}{5}$$

m=\frac{0±6\sqrt{10}}{10} tenglamasini yeching, bunda ± manfiy.

$$m=-\frac{3\sqrt{10}}{5}$$

Tenglama yechildi.

$$m=\frac{3\sqrt{10}}{5} m=-\frac{3\sqrt{10}}{5}$$