5a(x+2)+3(x+a)=4(x+3a)-5(1-ax) eching

$$5 a ( x + 2 ) + 3 ( x + a ) = 4 ( x + 3 a ) - 5 ( 1 - a x )$$

a uchun yechish

$$a=x-5$$

Yechim qadamlari

5a ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5ax+10a+3\left(x+a\right)=4\left(x+3a\right)-5\left(1-ax\right)$$

3 ga x+a ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5ax+10a+3x+3a=4\left(x+3a\right)-5\left(1-ax\right)$$

13a ni olish uchun 10a va 3a ni birlashtirish.

$$5ax+13a+3x=4\left(x+3a\right)-5\left(1-ax\right)$$

4 ga x+3a ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5ax+13a+3x=4x+12a-5\left(1-ax\right)$$

-5 ga 1-ax ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5ax+13a+3x=4x+12a-5+5ax$$

Ikkala tarafdan 12a ni ayirish.

$$5ax+13a+3x-12a=4x-5+5ax$$

a ni olish uchun 13a va -12a ni birlashtirish.

$$5ax+a+3x=4x-5+5ax$$

Ikkala tarafdan 5ax ni ayirish.

$$5ax+a+3x-5ax=4x-5$$

0 ni olish uchun 5ax va -5ax ni birlashtirish.

$$a+3x=4x-5$$

Ikkala tarafdan 3x ni ayirish.

$$a=4x-5-3x$$

x ni olish uchun 4x va -3x ni birlashtirish.

$$a=x-5$$

x uchun yechish

$$x=a+5$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

5a ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5ax+10a+3\left(x+a\right)=4\left(x+3a\right)-5\left(1-ax\right)$$

3 ga x+a ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5ax+10a+3x+3a=4\left(x+3a\right)-5\left(1-ax\right)$$

13a ni olish uchun 10a va 3a ni birlashtirish.

$$5ax+13a+3x=4\left(x+3a\right)-5\left(1-ax\right)$$

4 ga x+3a ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5ax+13a+3x=4x+12a-5\left(1-ax\right)$$

-5 ga 1-ax ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5ax+13a+3x=4x+12a-5+5xa$$

Ikkala tarafdan 4x ni ayirish.

$$5ax+13a+3x-4x=12a-5+5xa$$

-x ni olish uchun 3x va -4x ni birlashtirish.

$$5ax+13a-x=12a-5+5xa$$

Ikkala tarafdan 5xa ni ayirish.

$$5ax+13a-x-5xa=12a-5$$

0 ni olish uchun 5ax va -5xa ni birlashtirish.

$$13a-x=12a-5$$

Ikkala tarafdan 13a ni ayirish.

$$-x=12a-5-13a$$

-a ni olish uchun 12a va -13a ni birlashtirish.

$$-x=-a-5$$

Ikki tarafini -1 ga bo‘ling.

$$\frac{-x}{-1}=\frac{-a-5}{-1}$$

-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.

$$x=\frac{-a-5}{-1}$$

-a-5 ni -1 ga bo'lish.

$$x=a+5$$