5(x-3)+4(x+5)=20quad(x-7) eching

$$5 ( x - 3 ) + 4 ( x + 5 ) = 20 \quad ( x - 7 )$$

x uchun yechish

$$x = \frac{145}{11} = 13\frac{2}{11} \approx 13,181818182$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

5 ga x-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5x-15+4\left(x+5\right)=20\left(x-7\right)$$

4 ga x+5 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5x-15+4x+20=20\left(x-7\right)$$

9x ni olish uchun 5x va 4x ni birlashtirish.

$$9x-15+20=20\left(x-7\right)$$

5 olish uchun -15 va 20'ni qo'shing.

$$9x+5=20\left(x-7\right)$$

20 ga x-7 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$9x+5=20x-140$$

Ikkala tarafdan 20x ni ayirish.

$$9x+5-20x=-140$$

-11x ni olish uchun 9x va -20x ni birlashtirish.

$$-11x+5=-140$$

Ikkala tarafdan 5 ni ayirish.

$$-11x=-140-5$$

-145 olish uchun -140 dan 5 ni ayirish.

$$-11x=-145$$

Ikki tarafini -11 ga bo‘ling.

$$x=\frac{-145}{-11}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-145}{-11} kasrini \frac{145}{11} ga soddalashtirish mumkin.

$$x=\frac{145}{11}$$