5(x+2)-4(x-6)<8(x+3) eching

$$5 ( x + 2 ) - 4 ( x - 6 ) < 8 ( x + 3 )$$

x uchun yechish

$$x>\frac{10}{7}$$

Yechim qadamlari

5 ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5x+10-4\left(x-6\right)<8\left(x+3\right)$$

-4 ga x-6 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5x+10-4x+24<8\left(x+3\right)$$

x ni olish uchun 5x va -4x ni birlashtirish.

$$x+10+24<8\left(x+3\right)$$

34 olish uchun 10 va 24'ni qo'shing.

$$x+34<8\left(x+3\right)$$

8 ga x+3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$x+34<8x+24$$

Ikkala tarafdan 8x ni ayirish.

$$x+34-8x<24$$

-7x ni olish uchun x va -8x ni birlashtirish.

$$-7x+34<24$$

Ikkala tarafdan 34 ni ayirish.

$$-7x<24-34$$

-10 olish uchun 24 dan 34 ni ayirish.

$$-7x<-10$$

Ikki tarafini -7 ga bo‘ling. -7 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x>\frac{-10}{-7}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-10}{-7} kasrini \frac{10}{7} ga soddalashtirish mumkin.

$$x>\frac{10}{7}$$