5(x+2)-(x-1)(x+4)-6x eching

$$5 ( x + 2 ) - ( x - 1 ) ( x + 4 ) - 6 x$$

Baholash

$$14-4x-x^{2}$$

Yechim qadamlari

5 ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5x+10-\left(x-1\right)\left(x+4\right)-6x$$

x-1 ifodaning har bir elementini x+4 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$5x+10-\left(x^{2}+4x-x-4\right)-6x$$

3x ni olish uchun 4x va -x ni birlashtirish.

$$5x+10-\left(x^{2}+3x-4\right)-6x$$

x^{2}+3x-4 teskarisini topish uchun har birining teskarisini toping.

$$5x+10-x^{2}-3x-\left(-4\right)-6x$$

-4 ning teskarisi 4 ga teng.

$$5x+10-x^{2}-3x+4-6x$$

2x ni olish uchun 5x va -3x ni birlashtirish.

$$2x+10-x^{2}+4-6x$$

14 olish uchun 10 va 4'ni qo'shing.

$$2x+14-x^{2}-6x$$

-4x ni olish uchun 2x va -6x ni birlashtirish.

$$-4x+14-x^{2}$$

Kengaytirish

$$14-4x-x^{2}$$

Yechim qadamlari

5 ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$5x+10-\left(x-1\right)\left(x+4\right)-6x$$

x-1 ifodaning har bir elementini x+4 ifodaning har bir elementiga ko‘paytirish orqali taqsimot qonuni xususiyatlarini qo‘llash mumkin.

$$5x+10-\left(x^{2}+4x-x-4\right)-6x$$

3x ni olish uchun 4x va -x ni birlashtirish.

$$5x+10-\left(x^{2}+3x-4\right)-6x$$

x^{2}+3x-4 teskarisini topish uchun har birining teskarisini toping.

$$5x+10-x^{2}-3x-\left(-4\right)-6x$$

-4 ning teskarisi 4 ga teng.

$$5x+10-x^{2}-3x+4-6x$$

2x ni olish uchun 5x va -3x ni birlashtirish.

$$2x+10-x^{2}+4-6x$$

14 olish uchun 10 va 4'ni qo'shing.

$$2x+14-x^{2}-6x$$

-4x ni olish uchun 2x va -6x ni birlashtirish.

$$-4x+14-x^{2}$$