5(5x+8-4)<3(8x+7-4)+(2x+6x-9)-8(4x-7) eching

$$5 ( 5 x + 8 - 4 ) < 3 ( 8 x + 7 - 4 ) + ( 2 x + 6 x - 9 ) - 8 ( 4 x - 7 )$$

x uchun yechish

$$x<\frac{36}{25}$$

Yechim qadamlari

4 olish uchun 8 dan 4 ni ayirish.

$$5\left(5x+4\right)<3\left(8x+7-4\right)+2x+6x-9-8\left(4x-7\right)$$

5 ga 5x+4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$25x+20<3\left(8x+7-4\right)+2x+6x-9-8\left(4x-7\right)$$

3 olish uchun 7 dan 4 ni ayirish.

$$25x+20<3\left(8x+3\right)+2x+6x-9-8\left(4x-7\right)$$

3 ga 8x+3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$25x+20<24x+9+2x+6x-9-8\left(4x-7\right)$$

26x ni olish uchun 24x va 2x ni birlashtirish.

$$25x+20<26x+9+6x-9-8\left(4x-7\right)$$

32x ni olish uchun 26x va 6x ni birlashtirish.

$$25x+20<32x+9-9-8\left(4x-7\right)$$

0 olish uchun 9 dan 9 ni ayirish.

$$25x+20<32x-8\left(4x-7\right)$$

-8 ga 4x-7 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$25x+20<32x-32x+56$$

0 ni olish uchun 32x va -32x ni birlashtirish.

$$25x+20<56$$

Ikkala tarafdan 20 ni ayirish.

$$25x<56-20$$

36 olish uchun 56 dan 20 ni ayirish.

$$25x<36$$

Ikki tarafini 25 ga bo‘ling. 25 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$x<\frac{36}{25}$$