5(2-x)-3(x+2)=2(2x+2)-3(2+x)-3 eching

$$5 ( 2 - x ) - 3 ( x + 2 ) = 2 ( 2 x + 2 ) - 3 ( 2 + x ) - 3$$

x uchun yechish

$$x=1$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

5 ga 2-x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$10-5x-3\left(x+2\right)=2\left(2x+2\right)-3\left(2+x\right)-3$$

-3 ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$10-5x-3x-6=2\left(2x+2\right)-3\left(2+x\right)-3$$

-8x ni olish uchun -5x va -3x ni birlashtirish.

$$10-8x-6=2\left(2x+2\right)-3\left(2+x\right)-3$$

4 olish uchun 10 dan 6 ni ayirish.

$$4-8x=2\left(2x+2\right)-3\left(2+x\right)-3$$

2 ga 2x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4-8x=4x+4-3\left(2+x\right)-3$$

-3 ga 2+x ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4-8x=4x+4-6-3x-3$$

-2 olish uchun 4 dan 6 ni ayirish.

$$4-8x=4x-2-3x-3$$

x ni olish uchun 4x va -3x ni birlashtirish.

$$4-8x=x-2-3$$

-5 olish uchun -2 dan 3 ni ayirish.

$$4-8x=x-5$$

Ikkala tarafdan x ni ayirish.

$$4-8x-x=-5$$

-9x ni olish uchun -8x va -x ni birlashtirish.

$$4-9x=-5$$

Ikkala tarafdan 4 ni ayirish.

$$-9x=-5-4$$

-9 olish uchun -5 dan 4 ni ayirish.

$$-9x=-9$$

Ikki tarafini -9 ga bo‘ling.

$$x=\frac{-9}{-9}$$

1 ni olish uchun -9 ni -9 ga bo‘ling.

$$x=1$$