5*x+1/5+2x-3/6=1quad10 eching

$$5 \cdot \frac { x + 1 } { 5 } + \frac { 2 x - 3 } { 6 } = 1 \quad 10$$

x uchun yechish

$$x = \frac{57}{8} = 7\frac{1}{8} = 7,125$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 30 ga, 5,6 ning eng kichik karralisiga ko‘paytiring.

$$30\left(x+1\right)+5\left(2x-3\right)=30\times 10$$

30 ga x+1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$30x+30+5\left(2x-3\right)=30\times 10$$

5 ga 2x-3 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$30x+30+10x-15=30\times 10$$

40x ni olish uchun 30x va 10x ni birlashtirish.

$$40x+30-15=30\times 10$$

15 olish uchun 30 dan 15 ni ayirish.

$$40x+15=30\times 10$$

300 hosil qilish uchun 30 va 10 ni ko'paytirish.

$$40x+15=300$$

Ikkala tarafdan 15 ni ayirish.

$$40x=300-15$$

285 olish uchun 300 dan 15 ni ayirish.

$$40x=285$$

Ikki tarafini 40 ga bo‘ling.

$$x=\frac{285}{40}$$

\frac{285}{40} ulushini 5 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=\frac{57}{8}$$