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x uchun yechish
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5^{3x-7}=25
Tenglamani yechish uchun eksponent va logaritmlarning qoidalaridan foydalanish.
\log(5^{3x-7})=\log(25)
Tenglamaning ikkala tarafiga tegishli logaritmni chiqarish.
\left(3x-7\right)\log(5)=\log(25)
Darajaga ko'tarigan logaritm raqami raqam logaritmining darajasidir.
3x-7=\frac{\log(25)}{\log(5)}
Ikki tarafini \log(5) ga bo‘ling.
3x-7=\log_{5}\left(25\right)
Asosiy tenglamani almashtirish orqali \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
3x=2-\left(-7\right)
7 ni tenglamaning ikkala tarafiga qo'shish.
x=\frac{9}{3}
Ikki tarafini 3 ga bo‘ling.