5=ut+1/2at^2 eching

$$5 = u t + \frac { 1 } { 2 } a t ^ { 2 }$$

a uchun yechish

$$a=-\frac{2\left(tu-5\right)}{t^{2}}$$

$$t\neq 0$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$ut+\frac{1}{2}at^{2}=5$$

Ikkala tarafdan ut ni ayirish.

$$\frac{1}{2}at^{2}=5-ut$$

Tenglama standart shaklda.

$$\frac{t^{2}}{2}a=5-tu$$

Ikki tarafini \frac{1}{2}t^{2} ga bo‘ling.

$$\frac{2\times \frac{t^{2}}{2}a}{t^{2}}=\frac{2\left(5-tu\right)}{t^{2}}$$

\frac{1}{2}t^{2} ga bo'lish \frac{1}{2}t^{2} ga ko'paytirishni bekor qiladi.

$$a=\frac{2\left(5-tu\right)}{t^{2}}$$

t uchun yechish

$$\left\{\begin{matrix}t=-\frac{\sqrt{u^{2}+10a}+u}{a}\text{; }t=-\frac{-\sqrt{u^{2}+10a}+u}{a}\text{, }&a\neq 0\text{ and }a\geq -\frac{u^{2}}{10}\\t=\frac{5}{u}\text{, }&a=0\text{ and }u\neq 0\end{matrix}\right,$$