5+x^2=1 eching

$$5 + x ^ { 2 } = 1$$

x uchun yechish (complex solution)

$$x=-2i$$

$$x=2i$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 5 ni ayirish.

$$x^{2}=1-5$$

-4 olish uchun 1 dan 5 ni ayirish.

$$x^{2}=-4$$

Tenglama yechildi.

$$x=2i x=-2i$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 1 ni ayirish.

$$5+x^{2}-1=0$$

4 olish uchun 5 dan 1 ni ayirish.

$$4+x^{2}=0$$

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$x^{2}+4=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va 4 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 4}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 4}}{2}$$

-4 ni 4 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-16}}{2}$$

-16 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4i}{2}$$

x=\frac{0±4i}{2} tenglamasini yeching, bunda ± musbat.

$$x=2i$$

x=\frac{0±4i}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-2i$$

Tenglama yechildi.

$$x=2i x=-2i$$