4x+5-(4x*5x)= eching

$$4x+5-(4x \times 5x)=$$

Baholash

$$5+4x-20x^{2}$$

Yechim qadamlari

x^{2} hosil qilish uchun x va x ni ko'paytirish.

$$4x+5-4x^{2}\times 5$$

20 hosil qilish uchun 4 va 5 ni ko'paytirish.

$$4x+5-20x^{2}$$

Omil

$$-20\left(x-\frac{1-\sqrt{26}}{10}\right)\left(x-\frac{\sqrt{26}+1}{10}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

x^{2} hosil qilish uchun x va x ni ko'paytirish.

$$factor(4x+5-4x^{2}\times 5)$$

20 hosil qilish uchun 4 va 5 ni ko'paytirish.

$$factor(4x+5-20x^{2})$$

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$-20x^{2}+4x+5=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-4±\sqrt{4^{2}-4\left(-20\right)\times 5}}{2\left(-20\right)}$$

4 kvadratini chiqarish.

$$x=\frac{-4±\sqrt{16-4\left(-20\right)\times 5}}{2\left(-20\right)}$$

-4 ni -20 marotabaga ko'paytirish.

$$x=\frac{-4±\sqrt{16+80\times 5}}{2\left(-20\right)}$$

80 ni 5 marotabaga ko'paytirish.

$$x=\frac{-4±\sqrt{16+400}}{2\left(-20\right)}$$

16 ni 400 ga qo'shish.

$$x=\frac{-4±\sqrt{416}}{2\left(-20\right)}$$

416 ning kvadrat ildizini chiqarish.

$$x=\frac{-4±4\sqrt{26}}{2\left(-20\right)}$$

2 ni -20 marotabaga ko'paytirish.

$$x=\frac{-4±4\sqrt{26}}{-40}$$

x=\frac{-4±4\sqrt{26}}{-40} tenglamasini yeching, bunda ± musbat. -4 ni 4\sqrt{26} ga qo'shish.

$$x=\frac{4\sqrt{26}-4}{-40}$$

-4+4\sqrt{26} ni -40 ga bo'lish.

$$x=\frac{1-\sqrt{26}}{10}$$

x=\frac{-4±4\sqrt{26}}{-40} tenglamasini yeching, bunda ± manfiy. -4 dan 4\sqrt{26} ni ayirish.

$$x=\frac{-4\sqrt{26}-4}{-40}$$

-4-4\sqrt{26} ni -40 ga bo'lish.

$$x=\frac{\sqrt{26}+1}{10}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{1-\sqrt{26}}{10} ga va x_{2} uchun \frac{1+\sqrt{26}}{10} ga bo‘ling.

$$-20x^{2}+4x+5=-20\left(x-\frac{1-\sqrt{26}}{10}\right)\left(x-\frac{\sqrt{26}+1}{10}\right)$$