48^2+25=x^2 eching

$$48 ^ { 2 } + 25 = x ^ { 2 }$$

x uchun yechish

$$x=\sqrt{2329}\approx 48,259714048$$

$$x=-\sqrt{2329}\approx -48,259714048$$

Kvadrat ildizini topish bo'yicha qadamlar

2 daraja ko‘rsatkichini 48 ga hisoblang va 2304 ni qiymatni oling.

$$2304+25=x^{2}$$

2329 olish uchun 2304 va 25'ni qo'shing.

$$2329=x^{2}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$x^{2}=2329$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{2329} x=-\sqrt{2329}$$

Kvadrat tenglamalaridan foydalanish qoidalari

2 daraja ko‘rsatkichini 48 ga hisoblang va 2304 ni qiymatni oling.

$$2304+25=x^{2}$$

2329 olish uchun 2304 va 25'ni qo'shing.

$$2329=x^{2}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$x^{2}=2329$$

Ikkala tarafdan 2329 ni ayirish.

$$x^{2}-2329=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -2329 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-2329\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-2329\right)}}{2}$$

-4 ni -2329 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{9316}}{2}$$

9316 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{2329}}{2}$$

x=\frac{0±2\sqrt{2329}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{2329}$$

x=\frac{0±2\sqrt{2329}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{2329}$$

Tenglama yechildi.

$$x=\sqrt{2329} x=-\sqrt{2329}$$