x uchun yechish
x = \frac{15 \sqrt{5} - 15}{2} \approx 9,270509831
x=\frac{-15\sqrt{5}-15}{2}\approx -24,270509831
Grafik
Baham ko'rish
Klipbordga nusxa olish
450=2x\left(x+15\right)
\pi ni ikki tarafidan bekor qilish.
450=2x^{2}+30x
2x ga x+15 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
2x^{2}+30x=450
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
2x^{2}+30x-450=0
Ikkala tarafdan 450 ni ayirish.
x=\frac{-30±\sqrt{30^{2}-4\times 2\left(-450\right)}}{2\times 2}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 2 ni a, 30 ni b va -450 ni c bilan almashtiring.
x=\frac{-30±\sqrt{900-4\times 2\left(-450\right)}}{2\times 2}
30 kvadratini chiqarish.
x=\frac{-30±\sqrt{900-8\left(-450\right)}}{2\times 2}
-4 ni 2 marotabaga ko'paytirish.
x=\frac{-30±\sqrt{900+3600}}{2\times 2}
-8 ni -450 marotabaga ko'paytirish.
x=\frac{-30±\sqrt{4500}}{2\times 2}
900 ni 3600 ga qo'shish.
x=\frac{-30±30\sqrt{5}}{2\times 2}
4500 ning kvadrat ildizini chiqarish.
x=\frac{-30±30\sqrt{5}}{4}
2 ni 2 marotabaga ko'paytirish.
x=\frac{30\sqrt{5}-30}{4}
x=\frac{-30±30\sqrt{5}}{4} tenglamasini yeching, bunda ± musbat. -30 ni 30\sqrt{5} ga qo'shish.
x=\frac{15\sqrt{5}-15}{2}
-30+30\sqrt{5} ni 4 ga bo'lish.
x=\frac{-30\sqrt{5}-30}{4}
x=\frac{-30±30\sqrt{5}}{4} tenglamasini yeching, bunda ± manfiy. -30 dan 30\sqrt{5} ni ayirish.
x=\frac{-15\sqrt{5}-15}{2}
-30-30\sqrt{5} ni 4 ga bo'lish.
x=\frac{15\sqrt{5}-15}{2} x=\frac{-15\sqrt{5}-15}{2}
Tenglama yechildi.
450=2x\left(x+15\right)
\pi ni ikki tarafidan bekor qilish.
450=2x^{2}+30x
2x ga x+15 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.
2x^{2}+30x=450
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
\frac{2x^{2}+30x}{2}=\frac{450}{2}
Ikki tarafini 2 ga bo‘ling.
x^{2}+\frac{30}{2}x=\frac{450}{2}
2 ga bo'lish 2 ga ko'paytirishni bekor qiladi.
x^{2}+15x=\frac{450}{2}
30 ni 2 ga bo'lish.
x^{2}+15x=225
450 ni 2 ga bo'lish.
x^{2}+15x+\left(\frac{15}{2}\right)^{2}=225+\left(\frac{15}{2}\right)^{2}
15 ni bo‘lish, x shartining koeffitsienti, 2 ga \frac{15}{2} olish uchun. Keyin, \frac{15}{2} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.
x^{2}+15x+\frac{225}{4}=225+\frac{225}{4}
Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib \frac{15}{2} kvadratini chiqarish.
x^{2}+15x+\frac{225}{4}=\frac{1125}{4}
225 ni \frac{225}{4} ga qo'shish.
\left(x+\frac{15}{2}\right)^{2}=\frac{1125}{4}
x^{2}+15x+\frac{225}{4} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.
\sqrt{\left(x+\frac{15}{2}\right)^{2}}=\sqrt{\frac{1125}{4}}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
x+\frac{15}{2}=\frac{15\sqrt{5}}{2} x+\frac{15}{2}=-\frac{15\sqrt{5}}{2}
Qisqartirish.
x=\frac{15\sqrt{5}-15}{2} x=\frac{-15\sqrt{5}-15}{2}
Tenglamaning ikkala tarafidan \frac{15}{2} ni ayirish.
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