x uchun yechish
x = \frac{3 \sqrt{10}}{2} \approx 4,74341649
x = -\frac{3 \sqrt{10}}{2} \approx -4,74341649
Grafik
Baham ko'rish
Klipbordga nusxa olish
45=\frac{45}{2}+x^{2}
\frac{90}{4} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
\frac{45}{2}+x^{2}=45
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
x^{2}=45-\frac{45}{2}
Ikkala tarafdan \frac{45}{2} ni ayirish.
x^{2}=\frac{45}{2}
\frac{45}{2} olish uchun 45 dan \frac{45}{2} ni ayirish.
x=\frac{3\sqrt{10}}{2} x=-\frac{3\sqrt{10}}{2}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
45=\frac{45}{2}+x^{2}
\frac{90}{4} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
\frac{45}{2}+x^{2}=45
Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.
\frac{45}{2}+x^{2}-45=0
Ikkala tarafdan 45 ni ayirish.
-\frac{45}{2}+x^{2}=0
-\frac{45}{2} olish uchun \frac{45}{2} dan 45 ni ayirish.
x^{2}-\frac{45}{2}=0
Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{45}{2}\right)}}{2}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -\frac{45}{2} ni c bilan almashtiring.
x=\frac{0±\sqrt{-4\left(-\frac{45}{2}\right)}}{2}
0 kvadratini chiqarish.
x=\frac{0±\sqrt{90}}{2}
-4 ni -\frac{45}{2} marotabaga ko'paytirish.
x=\frac{0±3\sqrt{10}}{2}
90 ning kvadrat ildizini chiqarish.
x=\frac{3\sqrt{10}}{2}
x=\frac{0±3\sqrt{10}}{2} tenglamasini yeching, bunda ± musbat.
x=-\frac{3\sqrt{10}}{2}
x=\frac{0±3\sqrt{10}}{2} tenglamasini yeching, bunda ± manfiy.
x=\frac{3\sqrt{10}}{2} x=-\frac{3\sqrt{10}}{2}
Tenglama yechildi.
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