4+2sqrt{3}+2sqrt{3}+3=x+bsqrt{3} eching

$$4+2 \sqrt{ 3 } +2 \sqrt{ 3 } +3 = x+b \sqrt{ 3 }$$

b uchun yechish

$$b=-\frac{\sqrt{3}\left(x-4\sqrt{3}-7\right)}{3}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

4\sqrt{3} ni olish uchun 2\sqrt{3} va 2\sqrt{3} ni birlashtirish.

$$4+4\sqrt{3}+3=x+b\sqrt{3}$$

7 olish uchun 4 va 3'ni qo'shing.

$$7+4\sqrt{3}=x+b\sqrt{3}$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$x+b\sqrt{3}=7+4\sqrt{3}$$

Ikkala tarafdan x ni ayirish.

$$b\sqrt{3}=7+4\sqrt{3}-x$$

Tenglama standart shaklda.

$$\sqrt{3}b=-x+4\sqrt{3}+7$$

Ikki tarafini \sqrt{3} ga bo‘ling.

$$\frac{\sqrt{3}b}{\sqrt{3}}=\frac{-x+4\sqrt{3}+7}{\sqrt{3}}$$

\sqrt{3} ga bo'lish \sqrt{3} ga ko'paytirishni bekor qiladi.

$$b=\frac{-x+4\sqrt{3}+7}{\sqrt{3}}$$

7+4\sqrt{3}-x ni \sqrt{3} ga bo'lish.

$$b=\frac{\sqrt{3}\left(-x+4\sqrt{3}+7\right)}{3}$$

x uchun yechish

$$x=\sqrt{3}\left(4-b\right)+7$$