4+x^2=16+left(4-xright)^2 eching

$$4+ { x }^{ 2 } =16+ { \left(4-x \right) }^{ 2 }$$

x uchun yechish

$$x = \frac{7}{2} = 3\frac{1}{2} = 3,5$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(4-x\right)^{2} kengaytirilishi uchun ishlating.

$$4+x^{2}=16+16-8x+x^{2}$$

32 olish uchun 16 va 16'ni qo'shing.

$$4+x^{2}=32-8x+x^{2}$$

8x ni ikki tarafga qo’shing.

$$4+x^{2}+8x=32+x^{2}$$

Ikkala tarafdan x^{2} ni ayirish.

$$4+x^{2}+8x-x^{2}=32$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$4+8x=32$$

Ikkala tarafdan 4 ni ayirish.

$$8x=32-4$$

28 olish uchun 32 dan 4 ni ayirish.

$$8x=28$$

Ikki tarafini 8 ga bo‘ling.

$$x=\frac{28}{8}$$

\frac{28}{8} ulushini 4 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=\frac{7}{2}$$