4+x^2=left(6-xright)^2 eching

$$4+ { x }^{ 2 } = { \left(6-x \right) }^{ 2 }$$

x uchun yechish

$$x = \frac{8}{3} = 2\frac{2}{3} \approx 2,666666667$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(6-x\right)^{2} kengaytirilishi uchun ishlating.

$$4+x^{2}=36-12x+x^{2}$$

12x ni ikki tarafga qo’shing.

$$4+x^{2}+12x=36+x^{2}$$

Ikkala tarafdan x^{2} ni ayirish.

$$4+x^{2}+12x-x^{2}=36$$

0 ni olish uchun x^{2} va -x^{2} ni birlashtirish.

$$4+12x=36$$

Ikkala tarafdan 4 ni ayirish.

$$12x=36-4$$

32 olish uchun 36 dan 4 ni ayirish.

$$12x=32$$

Ikki tarafini 12 ga bo‘ling.

$$x=\frac{32}{12}$$

\frac{32}{12} ulushini 4 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=\frac{8}{3}$$