4+x^2=0+3 eching

$$4+ { x }^{ 2 } = 0+3$$

x uchun yechish (complex solution)

$$x=-i$$

$$x=i$$

Kvadrat ildizini topish bo'yicha qadamlar

3 olish uchun 0 va 3'ni qo'shing.

$$4+x^{2}=3$$

Ikkala tarafdan 4 ni ayirish.

$$x^{2}=3-4$$

-1 olish uchun 3 dan 4 ni ayirish.

$$x^{2}=-1$$

Tenglama yechildi.

$$x=i x=-i$$

Kvadrat tenglamalaridan foydalanish qoidalari

3 olish uchun 0 va 3'ni qo'shing.

$$4+x^{2}=3$$

Ikkala tarafdan 3 ni ayirish.

$$4+x^{2}-3=0$$

1 olish uchun 4 dan 3 ni ayirish.

$$1+x^{2}=0$$

Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.

$$x^{2}+1=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va 1 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4}}{2}$$

-4 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2i}{2}$$

x=\frac{0±2i}{2} tenglamasini yeching, bunda ± musbat.

$$x=i$$

x=\frac{0±2i}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-i$$

Tenglama yechildi.

$$x=i x=-i$$