4y-3/5n-4=5/3x+20/3 eching

$$4 y - \frac { 3 } { 5 } n - 4 = \frac { 5 } { 3 } x + \frac { 20 } { 3 }$$

n uchun yechish

$$n=\frac{20y}{3}-\frac{25x}{9}-\frac{160}{9}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan 4y ni ayirish.

$$-\frac{3}{5}n-4=\frac{5}{3}x+\frac{20}{3}-4y$$

4 ni ikki tarafga qo’shing.

$$-\frac{3}{5}n=\frac{5}{3}x+\frac{20}{3}-4y+4$$

\frac{32}{3} olish uchun \frac{20}{3} va 4'ni qo'shing.

$$-\frac{3}{5}n=\frac{5}{3}x+\frac{32}{3}-4y$$

Tenglama standart shaklda.

$$-\frac{3}{5}n=\frac{5x}{3}-4y+\frac{32}{3}$$

Tenglamaning ikki tarafini -\frac{3}{5} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.

$$\frac{-\frac{3}{5}n}{-\frac{3}{5}}=\frac{\frac{5x}{3}-4y+\frac{32}{3}}{-\frac{3}{5}}$$

-\frac{3}{5} ga bo'lish -\frac{3}{5} ga ko'paytirishni bekor qiladi.

$$n=\frac{\frac{5x}{3}-4y+\frac{32}{3}}{-\frac{3}{5}}$$

\frac{5x}{3}+\frac{32}{3}-4y ni -\frac{3}{5} ga bo'lish \frac{5x}{3}+\frac{32}{3}-4y ga k'paytirish -\frac{3}{5} ga qaytarish.

$$n=\frac{20y}{3}-\frac{25x}{9}-\frac{160}{9}$$

x uchun yechish

$$x=\frac{12y}{5}-\frac{9n}{25}-\frac{32}{5}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$\frac{5}{3}x+\frac{20}{3}=4y-\frac{3}{5}n-4$$

Ikkala tarafdan \frac{20}{3} ni ayirish.

$$\frac{5}{3}x=4y-\frac{3}{5}n-4-\frac{20}{3}$$

-\frac{32}{3} olish uchun -4 dan \frac{20}{3} ni ayirish.

$$\frac{5}{3}x=4y-\frac{3}{5}n-\frac{32}{3}$$

Tenglama standart shaklda.

$$\frac{5}{3}x=-\frac{3n}{5}+4y-\frac{32}{3}$$

Tenglamaning ikki tarafini \frac{5}{3} ga bo'lish, bu kasrni qaytarish orqali ikkala tarafga ko'paytirish bilan aynidir.

$$\frac{\frac{5}{3}x}{\frac{5}{3}}=\frac{-\frac{3n}{5}+4y-\frac{32}{3}}{\frac{5}{3}}$$

\frac{5}{3} ga bo'lish \frac{5}{3} ga ko'paytirishni bekor qiladi.

$$x=\frac{-\frac{3n}{5}+4y-\frac{32}{3}}{\frac{5}{3}}$$

4y-\frac{3n}{5}-\frac{32}{3} ni \frac{5}{3} ga bo'lish 4y-\frac{3n}{5}-\frac{32}{3} ga k'paytirish \frac{5}{3} ga qaytarish.

$$x=\frac{12y}{5}-\frac{9n}{25}-\frac{32}{5}$$