4y^2-9y-6561 eching

$$4 y ^ { 2 } - 9 y - 6561$$

Omil

$$4\left(y-\frac{9-9\sqrt{1297}}{8}\right)\left(y-\frac{9\sqrt{1297}+9}{8}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$4y^{2}-9y-6561=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$y=\frac{-\left(-9\right)±\sqrt{\left(-9\right)^{2}-4\times 4\left(-6561\right)}}{2\times 4}$$

-9 kvadratini chiqarish.

$$y=\frac{-\left(-9\right)±\sqrt{81-4\times 4\left(-6561\right)}}{2\times 4}$$

-4 ni 4 marotabaga ko'paytirish.

$$y=\frac{-\left(-9\right)±\sqrt{81-16\left(-6561\right)}}{2\times 4}$$

-16 ni -6561 marotabaga ko'paytirish.

$$y=\frac{-\left(-9\right)±\sqrt{81+104976}}{2\times 4}$$

81 ni 104976 ga qo'shish.

$$y=\frac{-\left(-9\right)±\sqrt{105057}}{2\times 4}$$

105057 ning kvadrat ildizini chiqarish.

$$y=\frac{-\left(-9\right)±9\sqrt{1297}}{2\times 4}$$

-9 ning teskarisi 9 ga teng.

$$y=\frac{9±9\sqrt{1297}}{2\times 4}$$

2 ni 4 marotabaga ko'paytirish.

$$y=\frac{9±9\sqrt{1297}}{8}$$

y=\frac{9±9\sqrt{1297}}{8} tenglamasini yeching, bunda ± musbat. 9 ni 9\sqrt{1297} ga qo'shish.

$$y=\frac{9\sqrt{1297}+9}{8}$$

y=\frac{9±9\sqrt{1297}}{8} tenglamasini yeching, bunda ± manfiy. 9 dan 9\sqrt{1297} ni ayirish.

$$y=\frac{9-9\sqrt{1297}}{8}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{9+9\sqrt{1297}}{8} ga va x_{2} uchun \frac{9-9\sqrt{1297}}{8} ga bo‘ling.

$$4y^{2}-9y-6561=4\left(y-\frac{9\sqrt{1297}+9}{8}\right)\left(y-\frac{9-9\sqrt{1297}}{8}\right)$$

Baholash

$$4y^{2}-9y-6561$$