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\left(2x-5\right)\left(2x+5\right)=0
Hisoblang: 4x^{2}-25. 4x^{2}-25 ni \left(2x\right)^{2}-5^{2} sifatida qaytadan yozish. Kvadratlarning farqini ushbu formula bilan hisoblash mumkin: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=\frac{5}{2} x=-\frac{5}{2}
Tenglamani yechish uchun 2x-5=0 va 2x+5=0 ni yeching.
4x^{2}=25
25 ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.
x^{2}=\frac{25}{4}
Ikki tarafini 4 ga bo‘ling.
x=\frac{5}{2} x=-\frac{5}{2}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
4x^{2}-25=0
Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 4\left(-25\right)}}{2\times 4}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 4 ni a, 0 ni b va -25 ni c bilan almashtiring.
x=\frac{0±\sqrt{-4\times 4\left(-25\right)}}{2\times 4}
0 kvadratini chiqarish.
x=\frac{0±\sqrt{-16\left(-25\right)}}{2\times 4}
-4 ni 4 marotabaga ko'paytirish.
x=\frac{0±\sqrt{400}}{2\times 4}
-16 ni -25 marotabaga ko'paytirish.
x=\frac{0±20}{2\times 4}
400 ning kvadrat ildizini chiqarish.
x=\frac{0±20}{8}
2 ni 4 marotabaga ko'paytirish.
x=\frac{5}{2}
x=\frac{0±20}{8} tenglamasini yeching, bunda ± musbat. \frac{20}{8} ulushini 4 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
x=-\frac{5}{2}
x=\frac{0±20}{8} tenglamasini yeching, bunda ± manfiy. \frac{-20}{8} ulushini 4 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.
x=\frac{5}{2} x=-\frac{5}{2}
Tenglama yechildi.