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4x^{2}-20x-5=0
Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.
x=\frac{-\left(-20\right)±\sqrt{\left(-20\right)^{2}-4\times 4\left(-5\right)}}{2\times 4}
ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.
x=\frac{-\left(-20\right)±\sqrt{400-4\times 4\left(-5\right)}}{2\times 4}
-20 kvadratini chiqarish.
x=\frac{-\left(-20\right)±\sqrt{400-16\left(-5\right)}}{2\times 4}
-4 ni 4 marotabaga ko'paytirish.
x=\frac{-\left(-20\right)±\sqrt{400+80}}{2\times 4}
-16 ni -5 marotabaga ko'paytirish.
x=\frac{-\left(-20\right)±\sqrt{480}}{2\times 4}
400 ni 80 ga qo'shish.
x=\frac{-\left(-20\right)±4\sqrt{30}}{2\times 4}
480 ning kvadrat ildizini chiqarish.
x=\frac{20±4\sqrt{30}}{2\times 4}
-20 ning teskarisi 20 ga teng.
x=\frac{20±4\sqrt{30}}{8}
2 ni 4 marotabaga ko'paytirish.
x=\frac{4\sqrt{30}+20}{8}
x=\frac{20±4\sqrt{30}}{8} tenglamasini yeching, bunda ± musbat. 20 ni 4\sqrt{30} ga qo'shish.
x=\frac{\sqrt{30}+5}{2}
20+4\sqrt{30} ni 8 ga bo'lish.
x=\frac{20-4\sqrt{30}}{8}
x=\frac{20±4\sqrt{30}}{8} tenglamasini yeching, bunda ± manfiy. 20 dan 4\sqrt{30} ni ayirish.
x=\frac{5-\sqrt{30}}{2}
20-4\sqrt{30} ni 8 ga bo'lish.
4x^{2}-20x-5=4\left(x-\frac{\sqrt{30}+5}{2}\right)\left(x-\frac{5-\sqrt{30}}{2}\right)
ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{5+\sqrt{30}}{2} ga va x_{2} uchun \frac{5-\sqrt{30}}{2} ga bo‘ling.