4x+2/5>6x-1 eching

$$4 x + \frac { 2 } { 5 } > 6 x - 1$$

x uchun yechish

$$x<\frac{7}{10}$$

Yechim qadamlari

Ikkala tarafdan 6x ni ayirish.

$$4x+\frac{2}{5}-6x>-1$$

-2x ni olish uchun 4x va -6x ni birlashtirish.

$$-2x+\frac{2}{5}>-1$$

Ikkala tarafdan \frac{2}{5} ni ayirish.

$$-2x>-1-\frac{2}{5}$$

-1 ni -\frac{5}{5} kasrga o‘giring.

$$-2x>-\frac{5}{5}-\frac{2}{5}$$

-\frac{5}{5} va \frac{2}{5} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$-2x>\frac{-5-2}{5}$$

-7 olish uchun -5 dan 2 ni ayirish.

$$-2x>-\frac{7}{5}$$

Ikki tarafini -2 ga bo‘ling. -2 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x<\frac{-\frac{7}{5}}{-2}$$

\frac{-\frac{7}{5}}{-2} ni yagona kasrga aylantiring.

$$x<\frac{-7}{5\left(-2\right)}$$

-10 hosil qilish uchun 5 va -2 ni ko'paytirish.

$$x<\frac{-7}{-10}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-7}{-10} kasrini \frac{7}{10} ga soddalashtirish mumkin.

$$x<\frac{7}{10}$$