4x+1/3<1/6+2 eching

$$4 x + \frac { 1 } { 3 } < \frac { 1 } { 6 } + 2$$

x uchun yechish

$$x<\frac{11}{24}$$

Yechim qadamlari

2 ni \frac{12}{6} kasrga o‘giring.

$$4x+\frac{1}{3}<\frac{1}{6}+\frac{12}{6}$$

\frac{1}{6} va \frac{12}{6} da bir xil maxraji bor, ularning suratini qo‘shish orqali qo‘shing.

$$4x+\frac{1}{3}<\frac{1+12}{6}$$

13 olish uchun 1 va 12'ni qo'shing.

$$4x+\frac{1}{3}<\frac{13}{6}$$

Ikkala tarafdan \frac{1}{3} ni ayirish.

$$4x<\frac{13}{6}-\frac{1}{3}$$

6 va 3 ning eng kichik umumiy karralisi 6 ga teng. \frac{13}{6} va \frac{1}{3} ni 6 maxraj bilan kasrlarga aylantirib oling.

$$4x<\frac{13}{6}-\frac{2}{6}$$

\frac{13}{6} va \frac{2}{6} da bir xil maxraji bor, ularning suratini ayirish orqali ayiring.

$$4x<\frac{13-2}{6}$$

11 olish uchun 13 dan 2 ni ayirish.

$$4x<\frac{11}{6}$$

Ikki tarafini 4 ga bo‘ling. 4 musbat bo‘lgani uchun, tengsizlik yo‘nalishi o‘zgarmaydi.

$$x<\frac{\frac{11}{6}}{4}$$

\frac{\frac{11}{6}}{4} ni yagona kasrga aylantiring.

$$x<\frac{11}{6\times 4}$$

24 hosil qilish uchun 6 va 4 ni ko'paytirish.

$$x<\frac{11}{24}$$