4r^2+4gamma+1=0 eching

$$4 r ^ { 2 } + 4 \gamma + 1 = 0$$

γ uchun yechish

$$\gamma =-r^{2}-\frac{1}{4}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Ikkala tarafdan 4r^{2} ni ayirish. Har qanday sonni noldan ayirsangiz, o‘zining manfiyi chiqadi.

$$4\gamma +1=-4r^{2}$$

Ikkala tarafdan 1 ni ayirish.

$$4\gamma =-4r^{2}-1$$

Ikki tarafini 4 ga bo‘ling.

$$\frac{4\gamma }{4}=\frac{-4r^{2}-1}{4}$$

4 ga bo'lish 4 ga ko'paytirishni bekor qiladi.

$$\gamma =\frac{-4r^{2}-1}{4}$$

-4r^{2}-1 ni 4 ga bo'lish.

$$\gamma =-r^{2}-\frac{1}{4}$$

r uchun yechish

$$r=\frac{\sqrt{-4\gamma -1}}{2}$$

$$r=-\frac{\sqrt{-4\gamma -1}}{2}\text{, }\gamma \leq -\frac{1}{4}$$