4c+6c^2 eching

$$4 c + 6 c ^ { 2 }$$

Omil

$$2c\left(3c+2\right)$$

Yechim qadamlari

2 omili.

$$2\left(2c+3c^{2}\right)$$

Hisoblang: 2c+3c^{2}. c omili.

$$c\left(2+3c\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$2c\left(3c+2\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$6c^{2}+4c=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$c=\frac{-4±\sqrt{4^{2}}}{2\times 6}$$

4^{2} ning kvadrat ildizini chiqarish.

$$c=\frac{-4±4}{2\times 6}$$

2 ni 6 marotabaga ko'paytirish.

$$c=\frac{-4±4}{12}$$

c=\frac{-4±4}{12} tenglamasini yeching, bunda ± musbat. -4 ni 4 ga qo'shish.

$$c=\frac{0}{12}$$

0 ni 12 ga bo'lish.

$$c=0$$

c=\frac{-4±4}{12} tenglamasini yeching, bunda ± manfiy. -4 dan 4 ni ayirish.

$$c=-\frac{8}{12}$$

\frac{-8}{12} ulushini 4 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$c=-\frac{2}{3}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun 0 ga va x_{2} uchun -\frac{2}{3} ga bo‘ling.

$$6c^{2}+4c=6c\left(c-\left(-\frac{2}{3}\right)\right)$$

p-\left(-q\right) shaklining barcha amallarigani p+q ga soddalashtiring.

$$6c^{2}+4c=6c\left(c+\frac{2}{3}\right)$$

Umumiy maxrajni topib va hisoblovchini qo'shish orqali \frac{2}{3} ni c ga qo'shing. So'ngra agar imkoni bo'lsa kasrni eng kam shartga qisqartiring.

$$6c^{2}+4c=6c\times \frac{3c+2}{3}$$

6 va 3 ichida eng katta umumiy 3 faktorini bekor qiling.

$$6c^{2}+4c=2c\left(3c+2\right)$$

Baholash

$$2c\left(3c+2\right)$$