E uchun yechish (complex solution)
\left\{\begin{matrix}E=-\frac{\left(y-9\right)\left(y-1\right)}{4X^{2}}\text{, }&X\neq 0\\E\in \mathrm{C}\text{, }&\left(y=1\text{ or }y=9\right)\text{ and }X=0\end{matrix}\right,
E uchun yechish
\left\{\begin{matrix}E=-\frac{\left(y-9\right)\left(y-1\right)}{4X^{2}}\text{, }&X\neq 0\\E\in \mathrm{R}\text{, }&\left(y=1\text{ or }y=9\right)\text{ and }X=0\end{matrix}\right,
X uchun yechish (complex solution)
\left\{\begin{matrix}X=-\frac{iE^{-\frac{1}{2}}\sqrt{y-9}\sqrt{y-1}}{2}\text{; }X=\frac{iE^{-\frac{1}{2}}\sqrt{y-9}\sqrt{y-1}}{2}\text{, }&E\neq 0\\X\in \mathrm{C}\text{, }&\left(y=1\text{ or }y=9\right)\text{ and }E=0\end{matrix}\right,
X uchun yechish
\left\{\begin{matrix}X=\frac{\sqrt{\frac{\left(1-y\right)\left(y-9\right)}{E}}}{2}\text{; }X=-\frac{\sqrt{\frac{\left(1-y\right)\left(y-9\right)}{E}}}{2}\text{, }&\left(y\leq 1\text{ and }E<0\right)\text{ or }\left(y\geq 9\text{ and }E<0\right)\text{ or }\left(y\leq 9\text{ and }y\geq 1\text{ and }E>0\right)\\X\in \mathrm{R}\text{, }&\left(y=1\text{ or }y=9\right)\text{ and }E=0\end{matrix}\right,
Grafik
Baham ko'rish
Klipbordga nusxa olish
4EX^{2}+y^{2}-10y+25=16
\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(y-5\right)^{2} kengaytirilishi uchun ishlating.
4EX^{2}-10y+25=16-y^{2}
Ikkala tarafdan y^{2} ni ayirish.
4EX^{2}+25=16-y^{2}+10y
10y ni ikki tarafga qo’shing.
4EX^{2}=16-y^{2}+10y-25
Ikkala tarafdan 25 ni ayirish.
4EX^{2}=-9-y^{2}+10y
-9 olish uchun 16 dan 25 ni ayirish.
4X^{2}E=-y^{2}+10y-9
Tenglama standart shaklda.
\frac{4X^{2}E}{4X^{2}}=\frac{\left(1-y\right)\left(y-9\right)}{4X^{2}}
Ikki tarafini 4X^{2} ga bo‘ling.
E=\frac{\left(1-y\right)\left(y-9\right)}{4X^{2}}
4X^{2} ga bo'lish 4X^{2} ga ko'paytirishni bekor qiladi.
4EX^{2}+y^{2}-10y+25=16
\left(a-b\right)^{2}=a^{2}-2ab+b^{2} binom teoremasini \left(y-5\right)^{2} kengaytirilishi uchun ishlating.
4EX^{2}-10y+25=16-y^{2}
Ikkala tarafdan y^{2} ni ayirish.
4EX^{2}+25=16-y^{2}+10y
10y ni ikki tarafga qo’shing.
4EX^{2}=16-y^{2}+10y-25
Ikkala tarafdan 25 ni ayirish.
4EX^{2}=-9-y^{2}+10y
-9 olish uchun 16 dan 25 ni ayirish.
4X^{2}E=-y^{2}+10y-9
Tenglama standart shaklda.
\frac{4X^{2}E}{4X^{2}}=\frac{\left(1-y\right)\left(y-9\right)}{4X^{2}}
Ikki tarafini 4X^{2} ga bo‘ling.
E=\frac{\left(1-y\right)\left(y-9\right)}{4X^{2}}
4X^{2} ga bo'lish 4X^{2} ga ko'paytirishni bekor qiladi.
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