4(1+x)^2=9 eching

$$4 ( 1 + x ) ^ { 2 } = 9$$

x uchun yechish

$$x=\frac{1}{2}=0,5$$

$$x = -\frac{5}{2} = -2\frac{1}{2} = -2,5$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikki tarafini 4 ga bo‘ling.

$$\frac{4\left(x+1\right)^{2}}{4}=\frac{9}{4}$$

4 ga bo'lish 4 ga ko'paytirishni bekor qiladi.

$$\left(x+1\right)^{2}=\frac{9}{4}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x+1=\frac{3}{2} x+1=-\frac{3}{2}$$

Tenglamaning ikkala tarafidan 1 ni ayirish.

$$x+1-1=\frac{3}{2}-1 x+1-1=-\frac{3}{2}-1$$

O‘zidan 1 ayirilsa 0 qoladi.

$$x=\frac{3}{2}-1 x=-\frac{3}{2}-1$$

\frac{3}{2} dan 1 ni ayirish.

$$x=\frac{1}{2}$$

-\frac{3}{2} dan 1 ni ayirish.

$$x=-\frac{5}{2}$$

Tenglama yechildi.

$$x=\frac{1}{2} x=-\frac{5}{2}$$