4x^2=(3(y-1)-4(25)/5) eching

$$4 { x }^{ 2 } =( \frac{ 3(y-1)-4(25) }{ 5 } )$$

y uchun yechish

$$y=\frac{20x^{2}+103}{3}$$

Chiziqli tenglamalarni yechish bo'yicha qadamlar

Tenglamaning ikkala tarafini 5 ga ko'paytirish.

$$20x^{2}=3\left(y-1\right)-4\times 25$$

3 ga y-1 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$20x^{2}=3y-3-4\times 25$$

100 hosil qilish uchun 4 va 25 ni ko'paytirish.

$$20x^{2}=3y-3-100$$

-103 olish uchun -3 dan 100 ni ayirish.

$$20x^{2}=3y-103$$

Tomonlarni almashtirib, barcha oʻzgaruvchi shartlar chap tomonga oʻtkazing.

$$3y-103=20x^{2}$$

103 ni ikki tarafga qo’shing.

$$3y=20x^{2}+103$$

Ikki tarafini 3 ga bo‘ling.

$$\frac{3y}{3}=\frac{20x^{2}+103}{3}$$

3 ga bo'lish 3 ga ko'paytirishni bekor qiladi.

$$y=\frac{20x^{2}+103}{3}$$

x uchun yechish (complex solution)

$$x=-\frac{\sqrt{15y-515}}{10}$$

$$x=\frac{\sqrt{15y-515}}{10}$$

x uchun yechish

$$x=\frac{\sqrt{15y-515}}{10}$$

$$x=-\frac{\sqrt{15y-515}}{10}\text{, }y\geq \frac{103}{3}$$