4sqrt{15/8}text{i}1/5sqrt{750} eching | Microsoft math hal qiluvchi

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https://socratic.org/questions/how-do-you-order-the-following-from-least-to-greatest-sqrt2-2-1-sqrt4-0-5-2

https://socratic.org/questions/what-is-4sqrt81-3-5-root3-8-2

https://socratic.org/questions/how-do-you-order-the-following-from-least-to-greatest-sqrt14-sqrt-49-36-3-3-5-3

https://math.stackexchange.com/questions/1219260/which-is-bigger-frac1-sqrt1001-sqrt1000-or-frac-110

https://socratic.org/questions/how-do-you-rationalize-the-denominator-and-simplify-sqrt15-sqrt15-sqrt13

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4i\times \frac{\sqrt{15}}{\sqrt{8}}\times \frac{1}{5}\sqrt{750}

\sqrt{\frac{15}{8}} boʻlinmasining kvadrat ildizini \frac{\sqrt{15}}{\sqrt{8}} kvadrat ildizlarining boʻlinmasi sifatida qayta yozing.

4i\times \frac{\sqrt{15}}{2\sqrt{2}}\times \frac{1}{5}\sqrt{750}

Faktor: 8=2^{2}\times 2. \sqrt{2^{2}\times 2} koʻpaytmasining kvadrat ildizini \sqrt{2^{2}}\sqrt{2} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing. 2^{2} ning kvadrat ildizini chiqarish.

4i\times \frac{\sqrt{15}\sqrt{2}}{2\left(\sqrt{2}\right)^{2}}\times \frac{1}{5}\sqrt{750}

\frac{\sqrt{15}}{2\sqrt{2}} maxrajini \sqrt{2} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.

4i\times \frac{\sqrt{15}\sqrt{2}}{2\times 2}\times \frac{1}{5}\sqrt{750}

\sqrt{2} kvadrati – 2.

4i\times \frac{\sqrt{30}}{2\times 2}\times \frac{1}{5}\sqrt{750}

\sqrt{15} va \sqrt{2} ni koʻpaytirish uchun kvadrat ildiz ichidagi sonlarni koʻpaytiring.

4i\times \frac{\sqrt{30}}{4}\times \frac{1}{5}\sqrt{750}

4 hosil qilish uchun 2 va 2 ni ko'paytirish.

\frac{4}{5}i\times \frac{\sqrt{30}}{4}\sqrt{750}

\frac{4}{5}i hosil qilish uchun 4i va \frac{1}{5} ni ko'paytirish.

\frac{4}{5}i\times \frac{\sqrt{30}}{4}\times 5\sqrt{30}

Faktor: 750=5^{2}\times 30. \sqrt{5^{2}\times 30} koʻpaytmasining kvadrat ildizini \sqrt{5^{2}}\sqrt{30} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing. 5^{2} ning kvadrat ildizini chiqarish.

4i\times \frac{\sqrt{30}}{4}\sqrt{30}

4i hosil qilish uchun \frac{4}{5}i va 5 ni ko'paytirish.

4i\times \frac{\sqrt{30}\sqrt{30}}{4}

\frac{\sqrt{30}}{4}\sqrt{30} ni yagona kasrga aylantiring.

4i\times \frac{30}{4}

30 hosil qilish uchun \sqrt{30} va \sqrt{30} ni ko'paytirish.

4i\times \frac{15}{2}

\frac{30}{4} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

30i

30i hosil qilish uchun 4i va \frac{15}{2} ni ko'paytirish.

Re(4i\times \frac{\sqrt{15}}{\sqrt{8}}\times \frac{1}{5}\sqrt{750})

\sqrt{\frac{15}{8}} boʻlinmasining kvadrat ildizini \frac{\sqrt{15}}{\sqrt{8}} kvadrat ildizlarining boʻlinmasi sifatida qayta yozing.

Re(4i\times \frac{\sqrt{15}}{2\sqrt{2}}\times \frac{1}{5}\sqrt{750})

Faktor: 8=2^{2}\times 2. \sqrt{2^{2}\times 2} koʻpaytmasining kvadrat ildizini \sqrt{2^{2}}\sqrt{2} kvadrat ildizlarining koʻpaytmasi sifatida qayta yozing. 2^{2} ning kvadrat ildizini chiqarish.

Re(4i\times \frac{\sqrt{15}\sqrt{2}}{2\left(\sqrt{2}\right)^{2}}\times \frac{1}{5}\sqrt{750})

\frac{\sqrt{15}}{2\sqrt{2}} maxrajini \sqrt{2} orqali surat va maxrajini koʻpaytirish orqali ratsionallashtiring.

Re(4i\times \frac{\sqrt{15}\sqrt{2}}{2\times 2}\times \frac{1}{5}\sqrt{750})

\sqrt{2} kvadrati – 2.

Re(4i\times \frac{\sqrt{30}}{2\times 2}\times \frac{1}{5}\sqrt{750})

\sqrt{15} va \sqrt{2} ni koʻpaytirish uchun kvadrat ildiz ichidagi sonlarni koʻpaytiring.

Re(4i\times \frac{\sqrt{30}}{4}\times \frac{1}{5}\sqrt{750})

4 hosil qilish uchun 2 va 2 ni ko'paytirish.

Re(\frac{4}{5}i\times \frac{\sqrt{30}}{4}\sqrt{750})

\frac{4}{5}i hosil qilish uchun 4i va \frac{1}{5} ni ko'paytirish.

Re(\frac{4}{5}i\times \frac{\sqrt{30}}{4}\times 5\sqrt{30})

Re(4i\times \frac{\sqrt{30}}{4}\sqrt{30})