4(x+5)+8geq5(x+2) eching

$$4 ( x + 5 ) + 8 \geq 5 ( x + 2 )$$

x uchun yechish

$$x\leq 18$$

Yechim qadamlari

4 ga x+5 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4x+20+8\geq 5\left(x+2\right)$$

28 olish uchun 20 va 8'ni qo'shing.

$$4x+28\geq 5\left(x+2\right)$$

5 ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$4x+28\geq 5x+10$$

Ikkala tarafdan 5x ni ayirish.

$$4x+28-5x\geq 10$$

-x ni olish uchun 4x va -5x ni birlashtirish.

$$-x+28\geq 10$$

Ikkala tarafdan 28 ni ayirish.

$$-x\geq 10-28$$

-18 olish uchun 10 dan 28 ni ayirish.

$$-x\geq -18$$

Ikki tarafini -1 ga bo‘ling. -1 manfiy boʻlgani uchun tengsizlikning yo‘nalishi o‘zgaradi.

$$x\leq \frac{-18}{-1}$$

Ikkala surat va maxrajdan manfiy belgini olib tashlash bilan \frac{-18}{-1} kasrini 18 ga soddalashtirish mumkin.

$$x\leq 18$$