3xleft(x-4right)=4x(x-4) eching

$$3x \left( x-4 \right) = 4x(x-4)$$

x uchun yechish

$$x=4$$

$$x=0$$

Faktorlash qadamlari

3x ga x-4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x^{2}-12x=4x\left(x-4\right)$$

4x ga x-4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x^{2}-12x=4x^{2}-16x$$

Ikkala tarafdan 4x^{2} ni ayirish.

$$3x^{2}-12x-4x^{2}=-16x$$

-x^{2} ni olish uchun 3x^{2} va -4x^{2} ni birlashtirish.

$$-x^{2}-12x=-16x$$

16x ni ikki tarafga qo’shing.

$$-x^{2}-12x+16x=0$$

4x ni olish uchun -12x va 16x ni birlashtirish.

$$-x^{2}+4x=0$$

x omili.

$$x\left(-x+4\right)=0$$

Tenglamani yechish uchun x=0 va -x+4=0 ni yeching.

$$x=0 x=4$$

Kvadrat tenglamalaridan foydalanish qoidalari

3x ga x-4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x^{2}-12x=4x\left(x-4\right)$$

4x ga x-4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x^{2}-12x=4x^{2}-16x$$

Ikkala tarafdan 4x^{2} ni ayirish.

$$3x^{2}-12x-4x^{2}=-16x$$

-x^{2} ni olish uchun 3x^{2} va -4x^{2} ni birlashtirish.

$$-x^{2}-12x=-16x$$

16x ni ikki tarafga qo’shing.

$$-x^{2}-12x+16x=0$$

4x ni olish uchun -12x va 16x ni birlashtirish.

$$-x^{2}+4x=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -1 ni a, 4 ni b va 0 ni c bilan almashtiring.

$$x=\frac{-4±\sqrt{4^{2}}}{2\left(-1\right)}$$

4^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-4±4}{2\left(-1\right)}$$

2 ni -1 marotabaga ko'paytirish.

$$x=\frac{-4±4}{-2}$$

x=\frac{-4±4}{-2} tenglamasini yeching, bunda ± musbat. -4 ni 4 ga qo'shish.

$$x=\frac{0}{-2}$$

0 ni -2 ga bo'lish.

$$x=0$$

x=\frac{-4±4}{-2} tenglamasini yeching, bunda ± manfiy. -4 dan 4 ni ayirish.

$$x=-\frac{8}{-2}$$

-8 ni -2 ga bo'lish.

$$x=4$$

Tenglama yechildi.

$$x=0 x=4$$

Kvadratni yakunlash bo'yicha qadamlar

3x ga x-4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x^{2}-12x=4x\left(x-4\right)$$

4x ga x-4 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x^{2}-12x=4x^{2}-16x$$

Ikkala tarafdan 4x^{2} ni ayirish.

$$3x^{2}-12x-4x^{2}=-16x$$

-x^{2} ni olish uchun 3x^{2} va -4x^{2} ni birlashtirish.

$$-x^{2}-12x=-16x$$

16x ni ikki tarafga qo’shing.

$$-x^{2}-12x+16x=0$$

4x ni olish uchun -12x va 16x ni birlashtirish.

$$-x^{2}+4x=0$$

Ikki tarafini -1 ga bo‘ling.

$$\frac{-x^{2}+4x}{-1}=\frac{0}{-1}$$

-1 ga bo'lish -1 ga ko'paytirishni bekor qiladi.

$$x^{2}+\frac{4}{-1}x=\frac{0}{-1}$$

4 ni -1 ga bo'lish.

$$x^{2}-4x=\frac{0}{-1}$$

0 ni -1 ga bo'lish.

$$x^{2}-4x=0$$

-4 ni bo‘lish, x shartining koeffitsienti, 2 ga -2 olish uchun. Keyin, -2 ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}-4x+\left(-2\right)^{2}=\left(-2\right)^{2}$$

-2 kvadratini chiqarish.

$$x^{2}-4x+4=4$$

x^{2}-4x+4 omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x-2\right)^{2}=4$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x-2\right)^{2}}=\sqrt{4}$$

Qisqartirish.

$$x-2=2 x-2=-2$$

2 ni tenglamaning ikkala tarafiga qo'shish.

$$x=4 x=0$$