36t^4+29t^2-7=0 eching

$$36 t ^ { 4 } + 29 t ^ { 2 } - 7 = 0$$

t uchun yechish

$$t=-\frac{\sqrt{7}}{6}\approx -0,440958552$$

$$t=\frac{\sqrt{7}}{6}\approx 0,440958552$$

Kvadrat tenglamalaridan foydalanish qoidalari

t^{2} uchun t ni almashtiring.

$$36t^{2}+29t-7=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni bu formula bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat tenglamada a uchun 36 ni, b uchun 29 ni va c uchun -7 ni ayiring.

$$t=\frac{-29±\sqrt{29^{2}-4\times 36\left(-7\right)}}{2\times 36}$$

Hisoblarni amalga oshiring.

$$t=\frac{-29±43}{72}$$

t=\frac{-29±43}{72} tenglamasini ± plus va ± minus boʻlgan holatida ishlang.

$$t=\frac{7}{36} t=-1$$

t=t^{2} boʻlganda, yechimlar musbat t uchun t=±\sqrt{t} hisoblanishi orqali olinadi.

$$t=\frac{\sqrt{7}}{6} t=-\frac{\sqrt{7}}{6}$$