35x^2+38x-41 eching

$$35 x ^ { 2 } + 38 x - 41$$

Omil

$$35\left(x-\frac{-2\sqrt{449}-19}{35}\right)\left(x-\frac{2\sqrt{449}-19}{35}\right)$$

Kvadrat tenglamalaridan foydalanish qoidalari

Kvadrat koʻp tenglama bu orqali hisoblanadi: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), bu yerda x_{1} va x_{2} ax^{2}+bx+c=0 kvadrat tenglamaning yechimlari.

$$35x^{2}+38x-41=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$x=\frac{-38±\sqrt{38^{2}-4\times 35\left(-41\right)}}{2\times 35}$$

38 kvadratini chiqarish.

$$x=\frac{-38±\sqrt{1444-4\times 35\left(-41\right)}}{2\times 35}$$

-4 ni 35 marotabaga ko'paytirish.

$$x=\frac{-38±\sqrt{1444-140\left(-41\right)}}{2\times 35}$$

-140 ni -41 marotabaga ko'paytirish.

$$x=\frac{-38±\sqrt{1444+5740}}{2\times 35}$$

1444 ni 5740 ga qo'shish.

$$x=\frac{-38±\sqrt{7184}}{2\times 35}$$

7184 ning kvadrat ildizini chiqarish.

$$x=\frac{-38±4\sqrt{449}}{2\times 35}$$

2 ni 35 marotabaga ko'paytirish.

$$x=\frac{-38±4\sqrt{449}}{70}$$

x=\frac{-38±4\sqrt{449}}{70} tenglamasini yeching, bunda ± musbat. -38 ni 4\sqrt{449} ga qo'shish.

$$x=\frac{4\sqrt{449}-38}{70}$$

-38+4\sqrt{449} ni 70 ga bo'lish.

$$x=\frac{2\sqrt{449}-19}{35}$$

x=\frac{-38±4\sqrt{449}}{70} tenglamasini yeching, bunda ± manfiy. -38 dan 4\sqrt{449} ni ayirish.

$$x=\frac{-4\sqrt{449}-38}{70}$$

-38-4\sqrt{449} ni 70 ga bo'lish.

$$x=\frac{-2\sqrt{449}-19}{35}$$

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right) formulasi yordamida amalni hisoblang. x_{1} uchun \frac{-19+2\sqrt{449}}{35} ga va x_{2} uchun \frac{-19-2\sqrt{449}}{35} ga bo‘ling.

$$35x^{2}+38x-41=35\left(x-\frac{2\sqrt{449}-19}{35}\right)\left(x-\frac{-2\sqrt{449}-19}{35}\right)$$

Baholash

$$35x^{2}+38x-41$$