33x^2-55x^2-1*5=1 eching

$$33 x ^ { 2 } - 55 x ^ { 2 } - 1 \cdot 5 = 1$$

x uchun yechish (complex solution)

$$x=-\frac{\sqrt{33}i}{11}\approx -0-0,522232968i$$

$$x=\frac{\sqrt{33}i}{11}\approx 0,522232968i$$

Kvadrat ildizini topish bo'yicha qadamlar

-22x^{2} ni olish uchun 33x^{2} va -55x^{2} ni birlashtirish.

$$-22x^{2}-1\times 5=1$$

5 hosil qilish uchun 1 va 5 ni ko'paytirish.

$$-22x^{2}-5=1$$

5 ni ikki tarafga qo’shing.

$$-22x^{2}=1+5$$

6 olish uchun 1 va 5'ni qo'shing.

$$-22x^{2}=6$$

Ikki tarafini -22 ga bo‘ling.

$$x^{2}=\frac{6}{-22}$$

\frac{6}{-22} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x^{2}=-\frac{3}{11}$$

Tenglama yechildi.

$$x=\frac{\sqrt{33}i}{11} x=-\frac{\sqrt{33}i}{11}$$

Kvadrat tenglamalaridan foydalanish qoidalari

-22x^{2} ni olish uchun 33x^{2} va -55x^{2} ni birlashtirish.

$$-22x^{2}-1\times 5=1$$

5 hosil qilish uchun 1 va 5 ni ko'paytirish.

$$-22x^{2}-5=1$$

Ikkala tarafdan 1 ni ayirish.

$$-22x^{2}-5-1=0$$

-6 olish uchun -5 dan 1 ni ayirish.

$$-22x^{2}-6=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} -22 ni a, 0 ni b va -6 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-22\right)\left(-6\right)}}{2\left(-22\right)}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-22\right)\left(-6\right)}}{2\left(-22\right)}$$

-4 ni -22 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{88\left(-6\right)}}{2\left(-22\right)}$$

88 ni -6 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-528}}{2\left(-22\right)}$$

-528 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4\sqrt{33}i}{2\left(-22\right)}$$

2 ni -22 marotabaga ko'paytirish.

$$x=\frac{0±4\sqrt{33}i}{-44}$$

x=\frac{0±4\sqrt{33}i}{-44} tenglamasini yeching, bunda ± musbat.

$$x=-\frac{\sqrt{33}i}{11}$$

x=\frac{0±4\sqrt{33}i}{-44} tenglamasini yeching, bunda ± manfiy.

$$x=\frac{\sqrt{33}i}{11}$$

Tenglama yechildi.

$$x=-\frac{\sqrt{33}i}{11} x=\frac{\sqrt{33}i}{11}$$