33t^4+1826t^2-750779=0 eching

$$33 t ^ { 4 } + 1826 t ^ { 2 } - 750779 = 0$$

t uchun yechish

$$t = -\frac{\sqrt{66 \sqrt{6402319} - 30129}}{33} \approx -11,21087248$$

$$t = \frac{\sqrt{66 \sqrt{6402319} - 30129}}{33} \approx 11,21087248$$

Kvadrat tenglamalaridan foydalanish qoidalari

t^{2} uchun t ni almashtiring.

$$33t^{2}+1826t-750779=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni bu formula bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat tenglamada a uchun 33 ni, b uchun 1826 ni va c uchun -750779 ni ayiring.

$$t=\frac{-1826±\sqrt{1826^{2}-4\times 33\left(-750779\right)}}{2\times 33}$$

Hisoblarni amalga oshiring.

$$t=\frac{-1826±4\sqrt{6402319}}{66}$$

t=\frac{-1826±4\sqrt{6402319}}{66} tenglamasini ± plus va ± minus boʻlgan holatida ishlang.

$$t=\frac{2\sqrt{6402319}}{33}-\frac{83}{3} t=-\frac{2\sqrt{6402319}}{33}-\frac{83}{3}$$

t=t^{2} boʻlganda, yechimlar musbat t uchun t=±\sqrt{t} hisoblanishi orqali olinadi.

$$t=\sqrt{\frac{2\sqrt{6402319}}{33}-\frac{83}{3}} t=-\sqrt{\frac{2\sqrt{6402319}}{33}-\frac{83}{3}}$$