33t^4+1826t^2-75779=0 eching

$$33 { t }^{ 4 } +1826 { t }^{ 2 } -75779 = 0$$

t uchun yechish (complex solution)

$$t = \frac{\sqrt{249}}{3} \approx 5,259911279$$

$$t = -\frac{\sqrt{249}}{3} \approx -5,259911279$$

$$t=-\sqrt{83}i\approx -0-9,110433579i$$

$$t=\sqrt{83}i\approx 9,110433579i$$

Kvadrat tenglamalaridan foydalanish qoidalari

t^{2} uchun t ni almashtiring.

$$33t^{2}+1826t-75779=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni bu formula bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat tenglamada a uchun 33 ni, b uchun 1826 ni va c uchun -75779 ni ayiring.

$$t=\frac{-1826±\sqrt{1826^{2}-4\times 33\left(-75779\right)}}{2\times 33}$$

Hisoblarni amalga oshiring.

$$t=\frac{-1826±3652}{66}$$

t=\frac{-1826±3652}{66} tenglamasini ± plus va ± minus boʻlgan holatida ishlang.

$$t=\frac{83}{3} t=-83$$

t=t^{2} boʻlganda, yechimlar har bir t uchun t=±\sqrt{t} hisoblanishi orqali olinadi.

$$t=-\frac{\sqrt{249}}{3} t=\frac{\sqrt{249}}{3} t=-\sqrt{83}i t=\sqrt{83}i$$

t uchun yechish

$$t = -\frac{\sqrt{249}}{3} \approx -5,259911279$$

$$t = \frac{\sqrt{249}}{3} \approx 5,259911279$$

Kvadrat tenglamalaridan foydalanish qoidalari

t^{2} uchun t ni almashtiring.

$$33t^{2}+1826t-75779=0$$

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni bu formula bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat tenglamada a uchun 33 ni, b uchun 1826 ni va c uchun -75779 ni ayiring.

$$t=\frac{-1826±\sqrt{1826^{2}-4\times 33\left(-75779\right)}}{2\times 33}$$

Hisoblarni amalga oshiring.

$$t=\frac{-1826±3652}{66}$$

t=\frac{-1826±3652}{66} tenglamasini ± plus va ± minus boʻlgan holatida ishlang.

$$t=\frac{83}{3} t=-83$$

t=t^{2} boʻlganda, yechimlar musbat t uchun t=±\sqrt{t} hisoblanishi orqali olinadi.

$$t=\frac{\sqrt{249}}{3} t=-\frac{\sqrt{249}}{3}$$