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3y^{2}=9
9 ni ikki tarafga qo’shing. Har qanday songa nolni qo‘shsangiz, o‘zi chiqadi.
y^{2}=\frac{9}{3}
Ikki tarafini 3 ga bo‘ling.
y^{2}=3
3 ni olish uchun 9 ni 3 ga bo‘ling.
y=\sqrt{3} y=-\sqrt{3}
Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.
3y^{2}-9=0
Bu kabi kvadrat tenglamalarni x^{2} sharti bilan, biroq x shartisiz hamon kvadrat tenglamasidan foydalanib yechish mumkin, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ular standart formulaga solingandan so'ng: ax^{2}+bx+c=0.
y=\frac{0±\sqrt{0^{2}-4\times 3\left(-9\right)}}{2\times 3}
Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 3 ni a, 0 ni b va -9 ni c bilan almashtiring.
y=\frac{0±\sqrt{-4\times 3\left(-9\right)}}{2\times 3}
0 kvadratini chiqarish.
y=\frac{0±\sqrt{-12\left(-9\right)}}{2\times 3}
-4 ni 3 marotabaga ko'paytirish.
y=\frac{0±\sqrt{108}}{2\times 3}
-12 ni -9 marotabaga ko'paytirish.
y=\frac{0±6\sqrt{3}}{2\times 3}
108 ning kvadrat ildizini chiqarish.
y=\frac{0±6\sqrt{3}}{6}
2 ni 3 marotabaga ko'paytirish.
y=\sqrt{3}
y=\frac{0±6\sqrt{3}}{6} tenglamasini yeching, bunda ± musbat.
y=-\sqrt{3}
y=\frac{0±6\sqrt{3}}{6} tenglamasini yeching, bunda ± manfiy.
y=\sqrt{3} y=-\sqrt{3}
Tenglama yechildi.