3x(x+2)-(x-1)-(x+3)(x-3)-2x^2 eching

$$3 x ( x + 2 ) - ( x - 1 ) - ( x + 3 ) ( x - 3 ) - 2 x ^ { 2 }$$

Baholash

$$5\left(x+2\right)$$

Yechim qadamlari

3x ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x^{2}+6x-\left(x-1\right)-\left(x+3\right)\left(x-3\right)-2x^{2}$$

x-1 teskarisini topish uchun har birining teskarisini toping.

$$3x^{2}+6x-x+1-\left(x+3\right)\left(x-3\right)-2x^{2}$$

5x ni olish uchun 6x va -x ni birlashtirish.

$$3x^{2}+5x+1-\left(x+3\right)\left(x-3\right)-2x^{2}$$

Hisoblang: \left(x+3\right)\left(x-3\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. 3 kvadratini chiqarish.

$$3x^{2}+5x+1-\left(x^{2}-9\right)-2x^{2}$$

x^{2}-9 teskarisini topish uchun har birining teskarisini toping.

$$3x^{2}+5x+1-x^{2}+9-2x^{2}$$

2x^{2} ni olish uchun 3x^{2} va -x^{2} ni birlashtirish.

$$2x^{2}+5x+1+9-2x^{2}$$

10 olish uchun 1 va 9'ni qo'shing.

$$2x^{2}+5x+10-2x^{2}$$

0 ni olish uchun 2x^{2} va -2x^{2} ni birlashtirish.

$$5x+10$$

Kengaytirish

$$5x+10$$

Yechim qadamlari

3x ga x+2 ni ko'paytirish orqali distributiv xususiyatdan foydalanish.

$$3x^{2}+6x-\left(x-1\right)-\left(x+3\right)\left(x-3\right)-2x^{2}$$

x-1 teskarisini topish uchun har birining teskarisini toping.

$$3x^{2}+6x-x+1-\left(x+3\right)\left(x-3\right)-2x^{2}$$

5x ni olish uchun 6x va -x ni birlashtirish.

$$3x^{2}+5x+1-\left(x+3\right)\left(x-3\right)-2x^{2}$$

Hisoblang: \left(x+3\right)\left(x-3\right). Ko‘paytirish qoida yordamida turli kvadratlarga aylantirilishi mumkin: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. 3 kvadratini chiqarish.

$$3x^{2}+5x+1-\left(x^{2}-9\right)-2x^{2}$$

x^{2}-9 teskarisini topish uchun har birining teskarisini toping.

$$3x^{2}+5x+1-x^{2}+9-2x^{2}$$

2x^{2} ni olish uchun 3x^{2} va -x^{2} ni birlashtirish.

$$2x^{2}+5x+1+9-2x^{2}$$

10 olish uchun 1 va 9'ni qo'shing.

$$2x^{2}+5x+10-2x^{2}$$

0 ni olish uchun 2x^{2} va -2x^{2} ni birlashtirish.

$$5x+10$$