3x^3y^6+81= eching

$$3 x ^ { 3 } y ^ { 6 } + 81 =$$

Omil

$$3\left(xy^{2}+3\right)\left(x^{2}y^{4}-3xy^{2}+9\right)$$

Yechim qadamlari

3 omili.

$$3\left(x^{3}y^{6}+27\right)$$

Hisoblang: x^{3}y^{6}+27. x^{3}y^{6}+27 ni \left(xy^{2}\right)^{3}+3^{3} sifatida qaytadan yozish. Kublar yigʻindisini ushbu formula bilan hisoblash mumkin: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).

$$\left(xy^{2}+3\right)\left(x^{2}y^{4}-3xy^{2}+9\right)$$

Toʻliq ajratilgan ifodani qaytadan yozing.

$$3\left(xy^{2}+3\right)\left(x^{2}y^{4}-3xy^{2}+9\right)$$

Baholash

$$3\left(x^{3}y^{6}+27\right)$$