3x^2-25x=0 eching

$$3 x ^ { 2 } - 25 x = 0$$

x uchun yechish

$$x = \frac{25}{3} = 8\frac{1}{3} \approx 8,333333333$$

$$x=0$$

Faktorlash qadamlari

x omili.

$$x\left(3x-25\right)=0$$

Tenglamani yechish uchun x=0 va 3x-25=0 ni yeching.

$$x=0 x=\frac{25}{3}$$

Kvadrat tenglamalaridan foydalanish qoidalari

ax^{2}+bx+c=0 shaklidagi barcha tenglamalarni kvadrat formulasi bilan yechish mumkin: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Kvadrat formula ikki yechmni taqdim qiladi, biri ± qo'shish bo'lganda, va ikkinchisi ayiruv bo'lganda.

$$3x^{2}-25x=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 3 ni a, -25 ni b va 0 ni c bilan almashtiring.

$$x=\frac{-\left(-25\right)±\sqrt{\left(-25\right)^{2}}}{2\times 3}$$

\left(-25\right)^{2} ning kvadrat ildizini chiqarish.

$$x=\frac{-\left(-25\right)±25}{2\times 3}$$

-25 ning teskarisi 25 ga teng.

$$x=\frac{25±25}{2\times 3}$$

2 ni 3 marotabaga ko'paytirish.

$$x=\frac{25±25}{6}$$

x=\frac{25±25}{6} tenglamasini yeching, bunda ± musbat. 25 ni 25 ga qo'shish.

$$x=\frac{50}{6}$$

\frac{50}{6} ulushini 2 ni chiqarib, bekor qilish hisobiga eng past shartlarga kamaytiring.

$$x=\frac{25}{3}$$

x=\frac{25±25}{6} tenglamasini yeching, bunda ± manfiy. 25 dan 25 ni ayirish.

$$x=\frac{0}{6}$$

0 ni 6 ga bo'lish.

$$x=0$$

Tenglama yechildi.

$$x=\frac{25}{3} x=0$$

Kvadratni yakunlash bo'yicha qadamlar

Bu kabi kvadrat tenglamalarni kvadratni yakunlab yechish mumkin. Kvadratni yechish uchun tenglama avval ushbu shaklda bo'lishi shart: x^{2}+bx=c.

$$3x^{2}-25x=0$$

Ikki tarafini 3 ga bo‘ling.

$$\frac{3x^{2}-25x}{3}=\frac{0}{3}$$

3 ga bo'lish 3 ga ko'paytirishni bekor qiladi.

$$x^{2}-\frac{25}{3}x=\frac{0}{3}$$

0 ni 3 ga bo'lish.

$$x^{2}-\frac{25}{3}x=0$$

-\frac{25}{3} ni bo‘lish, x shartining koeffitsienti, 2 ga -\frac{25}{6} olish uchun. Keyin, -\frac{25}{6} ning kvadratini tenglamaning ikkala tarafiga qo‘shing. Ushbu qadam tenglamaning chap qismini mukammal kvadrat sifatida hosil qiladi.

$$x^{2}-\frac{25}{3}x+\left(-\frac{25}{6}\right)^{2}=\left(-\frac{25}{6}\right)^{2}$$

Kasrning ham suratini, ham maxrajini kvadratga ko'paytirib -\frac{25}{6} kvadratini chiqarish.

$$x^{2}-\frac{25}{3}x+\frac{625}{36}=\frac{625}{36}$$

x^{2}-\frac{25}{3}x+\frac{625}{36} omili. Odatda, x^{2}+bx+c mukammal kvadrat bo'lsa, u doimo \left(x+\frac{b}{2}\right)^{2} omil sifatida bo'lishi mumkin.

$$\left(x-\frac{25}{6}\right)^{2}=\frac{625}{36}$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$\sqrt{\left(x-\frac{25}{6}\right)^{2}}=\sqrt{\frac{625}{36}}$$

Qisqartirish.

$$x-\frac{25}{6}=\frac{25}{6} x-\frac{25}{6}=-\frac{25}{6}$$

\frac{25}{6} ni tenglamaning ikkala tarafiga qo'shish.

$$x=\frac{25}{3} x=0$$