3x^2=15 eching

$$3 x ^ { 2 } = 15$$

x uchun yechish

$$x=\sqrt{5}\approx 2,236067977$$

$$x=-\sqrt{5}\approx -2,236067977$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikki tarafini 3 ga bo‘ling.

$$x^{2}=\frac{15}{3}$$

5 ni olish uchun 15 ni 3 ga bo‘ling.

$$x^{2}=5$$

Tenglamaning ikkala tarafining kvadrat ildizini chiqarish.

$$x=\sqrt{5} x=-\sqrt{5}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikki tarafini 3 ga bo‘ling.

$$x^{2}=\frac{15}{3}$$

5 ni olish uchun 15 ni 3 ga bo‘ling.

$$x^{2}=5$$

Ikkala tarafdan 5 ni ayirish.

$$x^{2}-5=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 1 ni a, 0 ni b va -5 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\left(-5\right)}}{2}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\left(-5\right)}}{2}$$

-4 ni -5 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{20}}{2}$$

20 ning kvadrat ildizini chiqarish.

$$x=\frac{0±2\sqrt{5}}{2}$$

x=\frac{0±2\sqrt{5}}{2} tenglamasini yeching, bunda ± musbat.

$$x=\sqrt{5}$$

x=\frac{0±2\sqrt{5}}{2} tenglamasini yeching, bunda ± manfiy.

$$x=-\sqrt{5}$$

Tenglama yechildi.

$$x=\sqrt{5} x=-\sqrt{5}$$