3x^2+40=12 eching

$$3 x ^ { 2 } + 40 = 12$$

x uchun yechish (complex solution)

$$x=-\frac{2\sqrt{21}i}{3}\approx -0-3,055050463i$$

$$x=\frac{2\sqrt{21}i}{3}\approx 3,055050463i$$

Kvadrat ildizini topish bo'yicha qadamlar

Ikkala tarafdan 40 ni ayirish.

$$3x^{2}=12-40$$

-28 olish uchun 12 dan 40 ni ayirish.

$$3x^{2}=-28$$

Ikki tarafini 3 ga bo‘ling.

$$x^{2}=-\frac{28}{3}$$

Tenglama yechildi.

$$x=\frac{2\sqrt{21}i}{3} x=-\frac{2\sqrt{21}i}{3}$$

Kvadrat tenglamalaridan foydalanish qoidalari

Ikkala tarafdan 12 ni ayirish.

$$3x^{2}+40-12=0$$

28 olish uchun 40 dan 12 ni ayirish.

$$3x^{2}+28=0$$

Ushbu tenglama standart shaklidadir: ax^{2}+bx+c=0. Kvadrat tenglama formulasida, \frac{-b±\sqrt{b^{2}-4ac}}{2a} 3 ni a, 0 ni b va 28 ni c bilan almashtiring.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\times 28}}{2\times 3}$$

0 kvadratini chiqarish.

$$x=\frac{0±\sqrt{-4\times 3\times 28}}{2\times 3}$$

-4 ni 3 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-12\times 28}}{2\times 3}$$

-12 ni 28 marotabaga ko'paytirish.

$$x=\frac{0±\sqrt{-336}}{2\times 3}$$

-336 ning kvadrat ildizini chiqarish.

$$x=\frac{0±4\sqrt{21}i}{2\times 3}$$

2 ni 3 marotabaga ko'paytirish.

$$x=\frac{0±4\sqrt{21}i}{6}$$

x=\frac{0±4\sqrt{21}i}{6} tenglamasini yeching, bunda ± musbat.

$$x=\frac{2\sqrt{21}i}{3}$$

x=\frac{0±4\sqrt{21}i}{6} tenglamasini yeching, bunda ± manfiy.

$$x=-\frac{2\sqrt{21}i}{3}$$

Tenglama yechildi.

$$x=\frac{2\sqrt{21}i}{3} x=-\frac{2\sqrt{21}i}{3}$$